How would you simplify #sqrt18 times sqrt2#?

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Answer 1 · 2018-08-03T23:38:09

#pm6#

We can move these inside the radical to get

#sqrt(36)#

We are able to do this because of the radical property

#sqrtasqrtb=sqrt(ab)#, assuming #a# and #b# are positive.

Knowing this is a perfect square, this easily simplifies to

#pm6#

Hope this helps!