How do you find the slope and intercept of #y=3/5x-1#?

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Answer 1 · 2018-08-03T06:41:01

Slope: #3/5#

x-intercept: #(5/3, 0)#

y-intercept: #(0, -1)#

#y = 3/5x - 1#

This equation is in slope-intercept form:
www.geogebra.org

Based on the image, we know that the slope is the value multiplied by #x#, so the slope is #3/5#.

We know the #y#-intercept is #b#, or #-1#, so it is at #(0, -1)#.

To find the #x#-intercept, plug in #0# for #y# and solve for #x#:
#0 = 3/5x - 1#

#1 = 3/5x#

#5/3 = x#

#x = 5/3#

The #x#-intercept is at #(5/3, 0)#.

Hope this helps!

Answer 2 · 2018-08-04T00:04:53

Slope #3/5#, #y#-intercept #-1#, #x#-intercept #5/3#

The good thing is that this equation is in slope-intercept form

#y=mx+b#, with slope #m# and a #y#-intercept of #b#.

By pattern matching, we see that our slope is #3/5#, and our #y#-intercept is #-1#.

We can go about finding our #x#-intercept by setting #y# equal to zero. We get

#3/5x-1=0=>3/5x=1=>x=5/3#

Therefore, our slope is #3/5#, our #y#-intercept is #-1#, and our #x#-intercept is #5/3#.

Hope this helps!