Question

How do you convert 0.45 g of sodium hydroxide, NaOH to moles?

Answer 1

We take the quotient...`n_"NaOH"="mass of sodium hydroxide"/"molar mass of sodium hydroxide"`

Explanation:

And so...

`n_"NaOH"=(0.450*g)/(40.00*g*mol^-1)=0.0113*mol`

Note the dimensional consistency of the answer. The `g` cancel...and we get an answer in `(cancelg)/(cancelg*mol^-1)=1/(mol^-1)=1/(1/(mol))=mol`...as required...