Anybody know the direction?

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1 Answer
A. S. Adikesavan
Aug 7, 2018

#253.3^o#

Explanation:

The polar form #( r, theta )# for

#( -3 - 10 )# = r ( cos theta, sin theta )# is

#( sqrt 109, 253,3^o )#, using

# r + sqrt( (-3)^2+(-10)^2) = sqrt109 and Q_3#

#theta = 180^o + arctan ( (-10)/(-3)) = 180^o + 73.3^o#

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