A proton with velocity v completes a circle with radius r in uniform magnetic field.what should be the velocity of alpha particle so that it completes a circle with same radius under the influence of the same magnetic field?
1 Answer
The force experienced by a particle of charge
(mv^2)/r=qvB_m
=>v=(qrB_m)/m
Where
In our problem both proton and
For proton the above relation becomes
=>v=(q_prB_m)/m_p
And for
=>v_alpha=(q_alpharB_m)/m_alpha
So
Hence