How do you evaluate #(4x^{-12}y^{10})(6x^{4}y^{3})#?

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Answer 1 · 2018-08-08T09:29:29

Please see below.

Let ,

#A=(4x^(-12)y^10)(6x^4y^3)#

Rearranged the like terms:

#A=(4 *6)(x^-12x^4)(y^10y^3)#

#A=24(x^(-12+4))(y^(10+3))to[becausea^mxxa^n=a^(m+n)]#

#:.A=24(x^-8)(y^13)#

#:.A=24x^-8 y^13 or A=(24y^13)/x^8#