What is the equation of the line between $(0,2)$ and $(23,0)$ ?

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Answer 1 · 2018-08-08T22:46:56

$y=(2/23)x+2$

I will solve for slope intercept form, $y=mx+b$

To find the equation given two points, I would use the slope formula to find the slope first

$m=(y_2-y_1)/(x_2-x_1)$

$m=(0--2)/(23-0)=2/23$

You do not have to find $b$ because it is the $y$ -intercept, which we already know is $(0,2)$

$y=(2/23)x+2$

Answer 2 · 2018-08-09T10:42:53

$color(indigo)(2x - 23y = 46, " is the equation in standard form"$

$A (0, 2), B (23, 0)$

Equation of $bar(AB)$ is given by the formula

$(y - y_a) / (y_b - y_a) = (x - x_a) / (x_b- x_a)$

$(y - 2) / (0 -2) = (x - 0) / (23 - 0)$

$(y-2) / -2 = x / 23$

$23y - 46 = -2x, " Cross multiplying,"$

$color(indigo)(2x - 23y = 46, " is the equation in standard form"$

What is the equation of the line between (0,2)(0,2) and (23,0)(23,0)?