How do you solve $2 ln (7x) = 4$ ?

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Answer 1 · 2018-08-09T12:05:37

$:.x=e^2/7$

Here ,

$2ln(7x)=4$ $where , x in RR^+$

$:.ln(7x)^2=4...to[becauselna^n=nlna]$

$:.(7x)^2=e^4....to[becauselny=k<=>y=e^k ]$

$:.7x=e^2$

$:.x=e^2/7$

Check :

$LHS=2ln(7x)=2ln(7*e^2/7)=2lne^2=4lne=4(1)=4$

How do you solve 2 ln (7x) = 42 ln (7x) = 4?