When air at 300k and 1 atm pressure is compressed to one.twentieth of its original volume and 30 atm pressure the new temperature will be?

1 Answer
Aug 9, 2018

Using the Gas equation for gases and inserting given values we get

(P_1V_1)/T_1=(P_2V_2)/T_2P1V1T1=P2V2T2
(1xxV_1)/300=(30xxV_1/20)/T_21×V1300=30×V120T2
=>T_2=(30xxV_1/20)/((1xxV_1)/300)T2=30×V1201×V1300
=>T_2=30xx300/20T2=30×30020
=>T_2=450\ sfK