Please help How do you graph the polar equation r=8-sec#theta# ?
1 Answer
See the explanation and graphs.
Explanation:
As sec values
r is periodic,with period
Short Table, for $theta in
The graph is symmetrical about
graph is outside the annular ( circular ) region # 7 < r < 9 ).
Converting to the Cartesian form, using
The Socratic graph is immediate, with asymptote x = 0.
graph{((x^2 + y^2)^0.5(1+1/x) - 8)(x+0.01y)=0[-40 40 -20 20]}
See the bounding circles
graph{((x^2 + y^2)^0.5(1+1/x) - 8)(x^2+y^2-49)(x^2+y^2-81)=0[-20 20 -10 10]}