What are the zeros of f(x) = x^2-8x+16?
1 Answer
Aug 10, 2018
Explanation:
Given:
f(x) = x^2-8x+16
We can recognise this as a perfect square trinomial, since it has the form:
A^2-2AB+B^2 = (A-B)^2
with
x^2-8x+16 = x^2-2(x)(4)+4^2 = (x-4)^2
So