What are the zeros of f(x) = x^2-8x+16?

1 Answer
Aug 10, 2018

x=4 with multiplicity 2

Explanation:

Given:

f(x) = x^2-8x+16

We can recognise this as a perfect square trinomial, since it has the form:

A^2-2AB+B^2 = (A-B)^2

with A=x and B=4 ...

x^2-8x+16 = x^2-2(x)(4)+4^2 = (x-4)^2

So f(x) has one repeated zero x=4 with multiplicity 2.