Question

How do you evaluate `log_2 8`?

Answer 1

`3`

Explanation:

`"using the "color(blue)"law of logarithms"`

`•color(white)(x)log_b x=nhArrx=b^n`

`"let "log_2 8=nhArr8=2^nrArrn=3`

`rArrlog_2 8=3`

Answer 2

Using logarithm properties we have

`log_2 8=log_2 2^3=3*log_2 2=3`