An object with a mass of 12 kg is on a surface with a kinetic friction coefficient of 2 . How much force is necessary to accelerate the object horizontally at 3 m/s^2?

1 Answer
Aug 12, 2018

The force is =271.2N

Explanation:

The coefficient of kinetic friction is

mu_k=F_r/N

The mass of the object is m=12kg

The acceleration due to gravity is g=9.8ms^-2

The normal reaction is N=12g

The coefficient of kinetic friction is mu_k=2

Therefore,

F_r=mu_kN=2*12g=24g

According to Newton's Second Law

F-F_r=ma

The acceleration is

a=3ms^-2

Therefore,

F=F_r+ma=24g+12*3=24g+36=271.2N