Question

How do yo write the orbital diagram for silver?

Answer 1

Well, we can write the electronic configuration of the silver atom...

Explanation:

A quick glance at the Periodic Table tells us that `Z_"Ag"=47`..and so for the NEUTRAL atom....

We use the Aufbau process to write the electronic distribution of the SILVER atom...

`underbrace(1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(6))_"electronic configuration of krypton"5s^(1)4d^(10)`

That the configuration shows `5s^(1)4d^(10)` RATHER than `5s^(2)4d^(9)` is POSSIBLY a result of Hund's rule...