How do you rewrite f(x)=x^2+12x+20 in vertex form?

1 Answer
Aug 12, 2018

x^2+12x+20=(x+6)^2-16 in vertex form

Explanation:

f(x)=x^2+12x+20

f'(x)=2x+12

A critical point of f(x) is :

2x+12=0<=> x=-6

so:

f(x)=(x+6)^2-16
And you can see on the graph below that the vertex form is respected.
graph{ y=x^2+12x+20 [-15,15,-20,20]}

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