If a^2 - 6b^2 - ab = 0a26b2ab=0, what is value of b/aba ?

2 Answers
Aug 14, 2018

-1/2, or, 1/312,or,13.

Explanation:

Given that, a^2-6b^2-ab=0a26b2ab=0.

:. 6b^2+ab-a^2=0.

:. ul(6b^2+3ab)-ul(2ab-a^2)=0.

:. 3b(2b+a)-a(2b+a)=0.

:. (2b+a)(3b-a)=0.

:. 2b+a=0, or, 3b-a=0.

:. 2b=-a, or, 3b=a.

:. b/a=-1/2, or, b/a=1/3.

Aug 14, 2018

b/a=1/3 orb/a=-1/2

Explanation:

Here ,

a^2-6b^2-ab=0

Dividing each term by a^2!=0

1-6b^2/a^2-b/a=0

=>6(b/a)^2+b/a-1=0

For simplicity take b/a=x

:.6x^2+x-1=0

=>6x^2+3x-2x-1=0

=>3x(2x+1)-1(2x+1)=0

=>(3x-1)(2x+1)=0

=>3x-1=0 or 2x+1=0

=>x=1/3 or x=-1/2

Subst. back x=b/a

:.b/a=1/3 orb/a=-1/2