# Average Velocity

## Key Questions

• Average velocity is defined as total displacement/ total time taken for that

Given, $s = 3 {t}^{2} - 6 t$

So,displacement in between $2 s$ and $5 s$ is $s = 3 {\left[{t}^{2}\right]}_{2}^{5} - 6 {\left[t\right]}_{2}^{5} = 3 \left(25 - 4\right) - 6 \left(5 - 2\right) = 45 m$

So,average velocity =$\frac{45}{5 - 2} = 15 m {s}^{-} 1$