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Featured 1 week ago

(a) Perimeter of the triangle ABC

(a)

Multiplying Eqn (1) by (3),

Substituting values of

Considering Equation (3),

Considering Eqn (2),

#80.68 - a_2 = (76.34/72) * a_2

Perimeter of the triangle ABC

Similarly, we can find P for Question (b)

Featured 1 week ago

Length of a leg

In triangle ABC in the above figure' hypotenuse vec(AB) = 30"

Using trigonometric functions,

Featured 6 days ago

Please see below.

I did not use the midpoint at all.

Using the equation of a circle:

Because it passes through

So,

Using the point

So,

Every circle that contains the points

Featured 4 days ago

Hence, the ratio in which the point divides the line is

We need to find the point of intersection of the lines

Simplifying the second line

Expanding

Rearanging and simplifying

Dividing by 13

or

The equations are:

Check

Verified.

Hence, the intersection point is

One end of the line is

Other end of the line is

Arranging in the form of

P divides AB in the ratio

Check:

Both are same

Justifying the coordinate for intersection point

Hence, the ratio in which the point divides the line is

Featured 2 days ago

#"the length of the arc is calculated using"#

#â€¢ " length of arc "="circumference "xx"fraction of circle"#

#color(white)(xxxxxxxxxxxx)=2pirxx60/360#

#color(white)(xxxxxxxxxxxx)=6pixxcancel(60)^1/cancel(360)^6#

#color(white)(xxxxxxxxxxxx)=(cancel(6) pi)/cancel(6)=pi~~3.14#

Featured 2 days ago

#"sum the parts of the ratio "#

#rArr4+3+2=9" parts"#

#â€¢ " the sum of the 3 angles in a triangle "=180^@#

#rArr180^@/9=20^@larrcolor(blue)"1 part"#

#rArr4" parts "=4xx20^@=80^@#

#rArr3" parts "=3xx20^@=60^@#

#rArr2" parts "=2xx20^@=40^@#

#"the 3 angles in the triangle are"#

#80^@,60^@" and "40^@#

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