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Answer:

#15/54# is the smallest

Explanation:

Often the easiest way to compare amounts is to give them all a common denominator.
Usually the easiest common denominator is a decimal, which you can find on a calculator.

#3/5 = 0.600#

#10/17 = 0.588#

#15/54 = 0.278# #larr# smallest

#60/121 = 0.496#
......................

In order from smallest to largest:
#15/54 = 0.278# #larr# smallest

#60/121 = 0.496#

#10/17 = 0.588#

#3/5 = 0.600#
...........................

Sometimes even the decimals themselves are confusing.
One thing that helps is to put each answer as MONEY.
Most people understand money very well! LOL!

(These values have been rounded to the nearest cent.)

#3/5 = 0.600# #larr# 60ȼ

#10/17 = 0.588# #larr# 59ȼ

#15/54 = 0.278# #larr# 28ȼ#larr# smallest

#60/121 = 0.496# #larr# 50ȼ

Now it is easy to see which one is the smallest and which one is the largest, and it's easy to put them in order.

Answer:

(D) #30#

Explanation:

Here's a good rule for this problem: All the factors for a number (except 1) must be able to be produced by a combination of products of the prime factors.

That might sound confusing. Let me give you an example. The prime factors for 42 are 2, 3, 7. The factors of 42 are 1, 2, 3, 6, 7, 14, 21, 42

#2=2#

#3=3#

#6=2*3#

#7=7#

#14=2*7#

#21=3*7#

#42=2*3*7#

See how I was able to form all the factors of 42 (except 1) by only multiplying the prime factors?

Using this rule, we just need to find the choice that has the number that can't be obtained by multiplying the prime factors:

(A) #10=2*5#
(B) #20=2*2*5#
(C) #25=5*5#
(E) #34=17*2#

Therefore, the answer must be (D) 30. Hope this helps!

Answer:

See a solution process below:

Explanation:

Find the prime factors for each number as:

#40 = 2 xx 2 xx 2 xx 5#

#42 = 2 xx 3 xx 7#

Now identify the common factors and determine the GCF:

#40 = color(red)(2) xx 2 xx 2 xx 5#

#42 = color(red)(2) xx 3 xx 7#

Therefore:

#"GCF" = color(red)(2)#

Answer:

#2/5#

Explanation:

You find a number that you can divide the denominator and numerator by and then you divide it by that number until you cant divide it no more.

In the above context we have;

#8/20#

#(4 xx 2)/(4 xx 5)#

#(cancel4 xx 2)/(cancel4 xx 5)#

#(1 xx 2)/(1 xx 5)#

#2/5#

Answer:

#2/5#

Explanation:

Divide both the numerator and denominator by the HCF.

#8/20#

IN this case:

#(8div4)/(20div4) = 2/5#

Answer:

The value of #x# is #63#
You can express this amount as "6 tens 3 ones."

Explanation:

I think the question has a typo where the #x#'s didn't show up.

I think the question should be:
If 49 tens 82 ones - 12 tens 96 ones = #x# + 293, then find the value of #x#

This question implies that "293" is too small, and it wants to know how much you'd need to add to make the answer correct.

Here is a good way to solve this problem.

1) For your own convenience, turn the bills into a sum of money.

49 tens  = $490
82 ones = $   82
......................................
Total . . . . . $572

12 tens  = $120
96 ones = $   96
.....................................
Total. . . . . .$216

Now you can write the question like this:
[49 tens 82 ones] #-# [12 tens 96 ones] #=# #x# + 293
[ . . . . . 572 . . . . . ] #-# [ . . . . . 216 . . . . . ] #=# #x# + 293

#572 - 216 = x + 293#
Solve for #x#

1) Combine like terms by doing the subtraction
#356 = x + 293#

2) Subtract 293 from both sides to isolate #x#
#63 = x larr# answer

Answer:
The value of #x# is #63#

Check:
#572 - 216# . . #=# . . . #63 + 293?#
. . . . #356# . . . . .#=# . . . . .#356#
#Check!#

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