Featured Answers

5
Active contributors today

Answer:

#(3div 3)/(9div3) = 1/3#

Explanation:

You can simplify a fraction if you multiply or divide the numerator and denominator by the same number.

This is the same as multiplying or dividing by #1#, which does not change the value of the fraction, but creates an equivalent fraction.

in #3/9#, both #3 and 9# have #3# as a factor. Divide both by #3#

#(3div 3)/(9div3) = 1/3#

Answer:

See a solution process below:

Explanation:

A formula for this problem can be written as:

#e = (p * h) + (r * b)#

Where:

#e# iw Angel's earnings: $160.25 for this problem.

#p# is Angel's hourly pay rate: $3 per hour for this problem.

#h# is the number of hours Angel worked: What we are solving for in this problem.

#r# is the rate Angel is paid for each ball found: $3.25 for this problem.

#b# is the number of balls found. For this problem we are told Angel found 15 balls per hour so we can write this as: #(15/"hr" * h)#

Substituting and solving for #h# gives:

#$160.25 = (($3)/"hr" * h) + ($3.25 * (15/"hr" * h))#

#$160.25 = (($3)/"hr" * h) + ($3.25 * 15/"hr" * h)#

#$160.25 = (($3)/"hr" * h) + (($48.75)/"hr" * h)#

#$160.25 = (($3)/"hr" + ($48.75)/"hr")h#

#$160.25 = ($51.75)/"hr"h#

#$160.25 xx color(red)("hr")/(color(red)($)color(blue)(51.75)) = ($51.75)/"hr"h xx color(red)("hr")/(color(blue)($)color(blue)(51.75))#

#color(blue)(cancel(color(black)($)))160.25 xx color(red)("hr")/(cancel(color(blue)($))color(blue)(51.75)) = color(blue)(cancel(color(black)($51.75)))/color(red)(cancel(color(black)("hr")))h xx cancel(color(red)("hr"))/cancel((color(blue)($)color(blue)(51.75)))#

#(160.25"hr")/color(blue)(51.75) = h#

#3.1"hr" = h#

Angel worked 3.1 hours rounded to the nearest tenth of an hour.

Answer:

Composite means it has more than two factors
Prime means that it only has one factor that it is itself and one

Explanation:

Composite - 25,12,21,15
Prime- 19,41

Factors of 25
5,1,25

Factors of 12
1,2,3,4,6,12

Factors of 21
1,3,7,21

Factors of 15
1,3,5,15

Factors of 19
1,19

Factors of 41
1,41

Answer:

168.

Explanation:

Answer:

See a solution process below:

Explanation:

Find the prime factors for each number as:

#40 = 2 xx 2 xx 2 xx 5#

#42 = 2 xx 3 xx 7#

Now identify the common factors and determine the GCF:

#40 = color(red)(2) xx 2 xx 2 xx 5#

#42 = color(red)(2) xx 3 xx 7#

Therefore:

#"GCF" = color(red)(2)#

Answer:

180

Explanation:

Find the unique prime factors for each number and multiply the factors together.

# 12 = 2 xx 2 xx 3 #
# 18 = 2 xx 3 xx 3 #
# 45 = 5 xx 3 xx 3 #

There are two factors of 2 needed ( the factor of 2 for 18 is a repeat.)

There are two factors of 3 needed ( the factors of 3 in 12 and 45 are repeats.)

There is one unique factor of 5

Multiplying the non repeated or unique factors gives.

The Least Common Multiply # = 2 xx 2 xx 3 xx 3 xx 5#

# 2 xx 2 xx 3 xx 3 xx 5 = 180#

View more
Questions
Ask a question Filters
Loading...
  • sprd65 answered · 1 week ago
This filter has no results, see all questions.
×
Question type

Use these controls to find questions to answer

Unanswered
Need double-checking
Practice problems
Conceptual questions