Question

1/2 secx cscx ?

Answer 1

`1/2*secx*cscx=1/2*1/cosx*1/sinx=1/(2sinxcosx)=1/(sin2x)=csc2x`.

Answer 2

`1/2cot(x)`

Explanation:

Recall that:
`sec(x)=1/cos(x)`
`csc(x)=1/sin(x)`
`cot(x)=cos(x)/sin(x)`

Substitute.
`1/(2sec(x))*csc(x)`
`1/(2(1/cos(x)))(1/sin(x))`
`cos(x)/2*1/sin(x)`
`cos(x)/(2sin(x))`
`1/2cot(x)`