(1 + 3i) (2 - ki) = 29(1+3i)(2−ki)=29 ?
1 Answer
Either that
or the
Explanation:
If
(1+3i)(2-6i) = 2+18 = 2color(red)(0)(1+3i)(2−6i)=2+18=20
So either there's a typo in the question (understandable since the
If
(1+3i)(2-ki) = 29(1+3i)(2−ki)=29
Divide both sides by
2-ki = 29/(1+3i) = (29(1-3i))/((1-3i)(1+3i)) = (29(1-3i))/102−ki=291+3i=29(1−3i)(1−3i)(1+3i)=29(1−3i)10
Hence:
ki = 2-(29(1-3i))/10 = (20-29(1-3i))/10 = (-9+87i)/10ki=2−29(1−3i)10=20−29(1−3i)10=−9+87i10
So:
k = 87/10+9/10ik=8710+910i