(1+3i)(2−ki)=29 ?
1 Answer
Aug 21, 2017
Either that
or the
Explanation:
If
(1+3i)(2−6i)=2+18=20
So either there's a typo in the question (understandable since the
If
(1+3i)(2−ki)=29
Divide both sides by
2−ki=291+3i=29(1−3i)(1−3i)(1+3i)=29(1−3i)10
Hence:
ki=2−29(1−3i)10=20−29(1−3i)10=−9+87i10
So:
k=8710+910i