#1/tanx + tanx =1/(sin x cosx)# ?

2 Answers
Noah G
Apr 10, 2018

I'm assuming you want us to prove that #1/tanx + tanx =1/(sinxcosx)#.

#1/(sinx/cosx) + sinx/cosx= 1/(sinxcosx)#

#cosx/sinx + sinx/cosx = 1/(sinxcosx)#

#(sin^2x + cos^2x)/(sinxcosx) =1/(sinxcosx)#

#1/(cosxsinx) = 1/(sinxcosx)#

#LHS = RHS#

As required.

Hopefully this helps!

P dilip_k
Apr 10, 2018

#LHS=1/tanx + tanx#

#=1/(sinx/cosx) + sinx/cosx#

#=cosx/sinx + sinx/cosx#

#=(cos^2x+sin^2x)/ (sinxcosx)#

# =1/(sin xcosx)=RHS#

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