May 12, 2018

${a}^{\frac{x}{n}} = \sqrt[n]{{a}^{x}}$

So if it is ${11}^{\frac{1}{7}}$

$a = 11$
$x = 1$
$n = 7$

Thus it will be
$\sqrt[7]{{11}^{1}}$

That is
$\sqrt[7]{11}$