-16x^2+8x-1=0?

2 Answers
Apr 18, 2018

x=1/4 or 0.25

Explanation:

So this is a quadratic with only 1 solution. I personally like to use the quadratic formula. Apply the following:

We dont have to re-write our numbers as they already follow the order we need them to be in.

So:

a=-16
b=8
c=-1

Now put these into this formula which is:

x=(-b+-sqrt(b^2-4ac))/(2a)

So we get: x=(-8+-sqrt(8^2(-4*-16*-1)))/(2*-16)

Now we simplify to get: x=(-8+-sqrt(64-64))/(-32)

Simplify further to get: x=(-8)/(-32)

Now divide by 8 on the denominator and the numerator to get:

(-1)/(-4)

Which is the same thing as 1/4 which is 0.25 but I personally like to keep them as fractions.

Hope this helps =)

Apr 19, 2018

x=1/4

Explanation:

In this quadratic, the negative at the beginning is not comfortable.

Divide the whole equation by -1

-16x^2 +8x-1=0 " "rarr" "16x^2-8x+1=0

This can factorise:
Find factors of 16 which add to 8.
Both brackets will have a negative sign.

(4x-1)(4x-1)=0

4x-1=0

4x=1

x=1/4