# 2.0 grams of ZnSO4 reacts completely with Li2CO3; how many grams of Li2SO4 would be produced?

Mar 6, 2018

1.362 grams

#### Explanation:

Thebalanced equation for the above reaction is:

$Z n S {O}_{4} + L {i}_{2} C {o}_{3} = Z n C {o}_{3} + L i 2 S {O}_{4}$

What is known as a double replacement.

Basically 1 mole reacts with 1 mole of te other and produces 1 mole ofeach by-product.

Molar mass of $Z n S {O}_{4} = 161.44$grams/mole
So 2 gm will be 0.01239 moles.

So the reaction produces 0.01239 moles. of $L i 2 S {O}_{4}$

Molar mass of $L i 2 S {O}_{4} = 109.95$ grams/mole

So you have : 0.01239 moles. x 109.95grams/mole = 1.362 grams.