2.00 L of 0.800 M #NaNO_3# must be prepared from a solution known to be 1.50 M in concentration. How many mL are required?

1 Answer
Aug 6, 2016

Answer:

1066.7mL of the 1.50M solution
or 1070 mL (3 sig figs)

Explanation:

When a solution is diluted the number of moles of solute, n, does not change so:

#n_"initial" = n_"final"#
or
#C_"initial" xx V_"initial" = C_"final" xx V_"final"#

#C_"initial" = 1.50 M#
#V_"initial" = ? mL#
#C_"final" = 0.800 M#
#V_"final" = 2.00 L = 2000 mL#

#V_"initial" = (C_"final" xx V_"final")/ C_"initial"#

#V_"initial" = (0.800 xx 2000)/ 1.50#

#V_"initial" = 1066.67 mL#