# 2.00 L of 0.800 M NaNO_3 must be prepared from a solution known to be 1.50 M in concentration. How many mL are required?

##### 1 Answer
Aug 6, 2016

1066.7mL of the 1.50M solution
or 1070 mL (3 sig figs)

#### Explanation:

When a solution is diluted the number of moles of solute, n, does not change so:

${n}_{\text{initial" = n_"final}}$
or
${C}_{\text{initial" xx V_"initial" = C_"final" xx V_"final}}$

${C}_{\text{initial}} = 1.50 M$
V_"initial" = ? mL
${C}_{\text{final}} = 0.800 M$
${V}_{\text{final}} = 2.00 L = 2000 m L$

${V}_{\text{initial" = (C_"final" xx V_"final")/ C_"initial}}$

${V}_{\text{initial}} = \frac{0.800 \times 2000}{1.50}$

${V}_{\text{initial}} = 1066.67 m L$