Question

2/a-2/b / 1/a^2 - 2/b^2 this is a division problem dealing with fractions and variables ?

Answer 1

`(2/a-2/b)/(1/a^2-2/b^2)=(2ab(b-a))/(b^2-2a^2)`

Explanation:

`(2/a-2/b)/(1/a^2-2/b^2`

= `((2b-2a)/(ab))/((b^2-2a^2)/(a^2b^2))`

= `(2b-2a)/(ab)xx(a^2b^2)/(b^2-2a^2)`

= `(2(b-a))/(ab)xx(abxxab)/(b^2-2a^2)`

= `(2(b-a))/cancel(ab)xx(cancel(ab)xxab)/(b^2-2a^2)`

= `(2ab(b-a))/(b^2-2a^2)`