#2"Na" + 2"H"_2"O"->2"NaOH" + "H"_2# What mass of sodium (#"Na"#) is needed to react with 8 grams of water (#"H"_2"O"#)? #"(Molar mass of Na" = 23 g//(mol); "molar mass of " "H"_2"O" = 18 g//(mol)")"# g_____Na

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zhirou Share
Feb 9, 2018

Answer:

#"10g"# of sodium. :)

Explanation:

This is our balanced equation:

#2Na + 2H_2O -> 2NaOH + H_2#

From this, we can tell that for every #1# mole of water that reacts, exactly #1# mole of sodium must also react.

#"8g"# of water is:

#8/("molar mass of water") = 8/18 = "0.44 moles"#

So, this means that #"0.44 moles"# of sodium must also react. Let's convert that to mass:

#0.44 xx "molar mass of sodium" = 0.44 xx 23 = "10g"#.

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