Question

2(sinx-sin^3 x)/cosx = sin2x ?

Answer 1

Very simple...

Formula Applied:-

• `color(red)(ul(bar(|color(green)(sin2x=2 cdot sinx cdot cosx))|`

• `color(red)(ul(bar(|color(blue)(sin^2x+cos^2x=1))|`

Explanation:

`2cdot (sinx-sin^3x)/cosx`

`=2 cdot (sinx(1-sin^2x))/cosx`

`=2 cdot (sinx cdot cos^2x)/cosx`

`=2cdot sinx cdot cosx`

`=sin2x`

Hope it helps...
Thank you...