# 2(sinx-sin^3 x)/cosx = sin2x ?

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Sunayan S
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Mar 9, 2018

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Very simple...

Formula Applied:-

#color(red)(ul(bar(|color(green)(sin2x=2 cdot sinx cdot cosx))|#

#color(red)(ul(bar(|color(blue)(sin^2x+cos^2x=1))|#

#### Explanation:

#2cdot (sinx-sin^3x)/cosx#

#=2 cdot (sinx(1-sin^2x))/cosx#

#=2 cdot (sinx cdot cos^2x)/cosx#

#=2cdot sinx cdot cosx#

#=sin2x# Hope it helps...

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