# 25x2-16y2-1=0 hyperbola? please!

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Narad T.
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Oct 20, 2017

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The equation of the hyperbola is

Comparing this equation to your equation

Rearranging your equation

Therefore,

The center of the hyperbola is

The vertices are

The foci are

graph{25x^2-16y^2-1=0 [-1.706, 1.712, -0.853, 0.855]}

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