3.0dm3 of sulfur dioxide is reacted with 2.0dm3 of oxygen according to the equation below. (2SO2)g+(O2)g(2SO3)g What volume of sulfur trioxide (in dm3 ) is formed?

Assume the reaction goes to completion and all gases are measured at the same temperature and pressure.

1 Answer
Jun 8, 2018

Consider,

2SO2(g)+O2(g)2SO3(g)

Given,

2.0dm31.43gdm3mol32g8.94102mol of O2, and

3.0dm32.62gdm3mol64.1g0.123mol of SO2

Alternatively you could use the ideal gas law to derive the moles, but I used density because I could look them up (on an exam the former is probably your method of choice).

From the preceding data, we can conclude that SO2 is the limiting reactant. We need twice as much, according to the stoichiometry, and dividing it by two gives us nSO2<nO2. Hence,

0.123mol2SO32SO280.1gmoldm32.62g3.76dm3 of SO3

would ideally be produced.