Question

`(3x^2-9x)÷(x^2-4x+3)`?

Answer 1

`=(3x)/(x-1)`

Explanation:

Factorise each bracket first:

`(3x^2-9x)/(x^2-4x+3)`

`=(3x(x-3))/((x-3)(x-1))`

`=(3xcancel((x-3)))/(cancel((x-3))(x-1))`

`=(3x)/(x-1)`