3x^3+x^2=48x+16?

solve polynomial equations setting all terms to zero

1 Answer
Nov 4, 2017

x_1=-4, x_2=-1/3 and x_3=4

Explanation:

3x^3+x^2=48x+16

3x^3-48x+x^2-16=0

3x*(x^2-16)+x^2-16=0

(3x+1)*(x^2-16)=0

(3x+1)(x+4)(x-4)=0

Hence x_1=-4, x_2=-1/3 and x_3=4