#48^2+52^2+63^2=#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Veddesh #phi# Jan 3, 2016 #8977# Explanation: #rarr##48^2=48*48=2304# #rarr##52^2=52*52=2704# #rarr##63^2=63*63=3969# #So##...2304+2704+3969=8977# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 2183 views around the world You can reuse this answer Creative Commons License