# 5.85 g of NaCl is dissolved in 1 L of pure water . How do you calculate the number of ions in 1mL of this solution?

Jul 11, 2014

5.85 g of NaCl = 0.1 mol
1 L solution contain NaCl = 0.1 mol
1 ml solution contain NaCl = 0.0001 mol

one NaCl ionized Na+ and Cl- so that produce 2 ions

Total ion mole in 1 ml = 2x0.0001 mol

Number of iron in 1 ml= $2$x$0.0001$x$6.023$x${10}^{23}$

Number of iron in 1 ml = $1.2$x${10}^{20}$ ions