Question #e1f0a
1 Answer
Mar 18, 2014
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
There are 0.1357 mol of AgNO₃ in the solution.
The volume of NaCl required is 271 mL.
23.05 g AgNO₃ ×
NaCl(s) → Na⁺(aq) + Cl⁻(aq)
AgNO₃(s) → Ag⁺(aq) + NO₃⁻(aq)
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
0.1357 mol AgNO₃ ×
0.1357 mol Cl⁻ ×
271 mL NaCl