Apr 27, 2014

We can find the effect of temperature on the Volume using the Charles' law equation.

${V}_{1}$ / ${T}_{1}$ = ${V}_{2}$ / ${T}_{2}$

${V}_{1}$ = 0.525 L , ${T}_{1}$ = 273 + 10 = 283 K

${V}_{2}$ = ? , ${T}_{2}$= 273 + 40 = 313 K

0.525 L / 283 K = ${V}_{2}$ / 313 K

0.525 L x 313 K / 283 K = ${V}_{2}$

${V}_{2}$ = L K/ 351 K = 315.17 L

${V}_{2}$ = 0.580 L.