Question #7b4e4

1 Answer
Apr 27, 2014

To solve this problem , we will need to use the ideal gas equation;

#P_1 V_1#= nR#T_1#

#V_1# = 10.1 L

#T_1# = 273 + 25 = 298 K

n = mass / molar mass = 1.25 g / 20.1 g#mol^-1# = 0.062 mol

#P_1# 10.1 L = 0.062 mol x 298 K x 8.314 J #K^-1# #mol^-1#

#P_1# = 0.062 mol x 298 K x 8.314 J #K^-1# #mol^-1# / 10.1 L

#P_1# = 15.20 atm

We can find the effect of temperature on the pressure using the P-T law.

#P_1 # / #T_1# = #P_2# / #T_2#

15.20 atm / 298 K = #P_2# / 323K

15.20 atm x 323 K / 298 K = #P_2#

#P_2# = 4909.6 atm K / 298 K = 16.47 atm