How do I prepare 1 L of 2 mol/L phenylmagnesium bromide?
1 Answer
Oct 3, 2014
Here are the theoretical calculations for 1 L of 2 mol/L PhMgBr.
Explanation:
PhBr + Mg → PhMgBr
1 or 2 crystals of I₂
Enough dry THF to make 1 L
Note: The I₂ acts as a catalyst for the reaction. You often use a large excess of Mg, up to 2 or 3 times the theoretical amount.
Note: The calculated amounts can have only one significant figure because that is all you gave for the molarity of the solution. If you need more precision, you will have to recalculate.