Question #d001e

1 Answer
Aug 7, 2015

I found; #d=(Vv)/E=2xx10^-4m=0.2mm#

Explanation:

Observing the units of your data (supposing they are all you need to solve this problem) you have:
#E=7.5xx10^7V/m#
#Vv=15000V#
We can try to combine them to get a distance #d# as:
#d=(Vv)/E=(15000V)/(7.5xx10^7V/m)=2xx10^-4m=0.2mm#