Question

Question #6ad4d

Answer 1

After t/2 seconds it has travelled a quarter of the total distance. This means that if the height of the tower is `h` then it has fallen a distance of `h/4` so is at a distance of `(3h)/4` above the ground.

Explanation:

`h_t=(1)/(2)g.t^2`

Where `h_t` is the total height and g is the acceleration due to gravity.

After `(t)/2` seconds :

`h_(t/2)=(1)/(2)g((t)/(2))^2`

`=g(t^2)/(8)`

So `h_t=4h_(t(1)/(2))`

So you can see that after half the time it has travelled a quarter of the distance.

This means that if the height of the tower is `h` then it has fallen a distance of `h/4` so is at a distance of `(3h)/4` above the ground.