Question #6ad4d

1 Answer
Oct 10, 2014

Answer:

After t/2 seconds it has travelled a quarter of the total distance. This means that if the height of the tower is #h# then it has fallen a distance of #h/4# so is at a distance of #(3h)/4# above the ground.

Explanation:

#h_t=(1)/(2)g.t^2#

Where #h_t# is the total height and g is the acceleration due to gravity.

After #(t)/2# seconds :

#h_(t/2)=(1)/(2)g((t)/(2))^2#

#=g(t^2)/(8)#

So #h_t=4h_(t(1)/(2))#

So you can see that after half the time it has travelled a quarter of the distance.

This means that if the height of the tower is #h# then it has fallen a distance of #h/4# so is at a distance of #(3h)/4# above the ground.