# Question 1423e

Dec 2, 2014

Q=mc(T'-T)
where:
Q=energy/heat
m=mass of the body
T'=final temperature of the body
T=initial temperature of the body

2000=240x(c)x(26-2)
c=2000/(240)(24) =0.3 J/g""^@C#

Dec 4, 2014

Specific heat capacity is the quantity of heat in Joules or calories required to raise the temperature of a substance by one degree Celsius. The equation for heat capacity is Q = (c)(m)($\Delta$T), where
Q = the heat energy
c = specific heat capacity
m = mass
$\Delta$T = change in temperature (final T - initial T)

Given :
Q = 2000J
m = 240 g
$\Delta$T = (26°C - 2°C) = 24°C

Unknown :
c

Equation :
Q = (c)(m)($\Delta$T)

Solution :
Divide both sides of the equation by m and $\Delta$T. Solve for c.
$\text{c}$ = $\text{Q}$$/$(m)($\Delta$T)

$\text{c}$ = $\text{2000 J/(240 g)(24°C)}$ = $\text{0.3 J/g°C}$
(rounded to one significant figure because 2000 J has only one significant figure)