# Question #81931

Jan 7, 2015

Let's take them one at a time...

Ammonium sulphate - ${\left(N {H}_{4}\right)}_{2} S {O}_{4}$ - $S {O}_{4}^{2 -}$ is the sulphate ion;

Zinc sulphide - $Z n S$

Aluminium carbonate - $A {l}_{2} {\left(C {O}_{3}\right)}_{3}$ - $C {O}_{3}^{2 -}$ is the carbonate ion;

Potassium sulphite - ${K}_{2} S {O}_{3}$ - $S {O}_{3}^{2 -}$ is the sulfite ion;

${\left(N {H}_{4}\right)}_{2} C 2 {O}_{4}$ - ammonium oxalate - $N {H}_{4}^{+}$ is the ammonium ion and ${C}_{2} {O}_{4}^{-}$ is the oxalate ion;

$A {l}_{2} {\left(S {O}_{4}\right)}_{3}$ - aluminium sulfate - $S {O}_{4}^{-}$ is the sulfate ion;

${\left(N {H}_{4}\right)}_{3} P {O}_{4}$ - ammonium phosphate - again, $N {H}_{4}^{+}$ is the ammonium ion, while $P {O}_{4}^{3 -}$ is the phosphate ion;

$L {i}_{3} N$ - Lithium nitride;

Now for the last one, $N a {\left(C {H}_{3} C O O\right)}_{2}$. Could you have mistyped the compound?

$N a \left(C {H}_{3} C O O\right)$ is sodium acetate, the salt of acetic acid. Since you have $N {a}^{+}$ and $C {H}_{3} C O {O}^{-}$, there cannot be a 2 subscript in the formula.

Another possible compound is $N a H {\left(C {H}_{3} C O O\right)}_{2}$, sodium diacetate.

There are quite a few online quizzes that can help you practice naming ionic compounds, here's a link to one:

http://www.quia.com/rr/180365.html