Question #4b660

1 Answer
Jan 29, 2015

#5.1×10^5"J"# of work are done.

Explanation:

#5.1xx10^(-5)J# of work are done.

If Q coulombs of charge is moved through a p.d of 1 volt 1 Joule of work is done.

So #-8.5muC# moved through #6V# requires #-8.5 xx10^(-6) xx6=-5.1xx10^(-5)J#

So the work done = #5.1xx10^(-5)J#