# Question c233b

Feb 4, 2015

In order to solve this problem you must use a couple of unit conversions in the form of conversion factors. Likewise, you'll need the formula for density, which is defined as mass per unit of volume.

$\rho = \frac{m}{V} \implies V = \frac{m}{\rho}$

You can either convert pounds to kg or kg to pounds, but you must convert ${\text{m}}^{3}$ to $\text{mL}$ for the expression of the sample's volume. So,

$1.36 \cdot {10}^{4} \text{kg"/"m"^(3) * ("2.2046 lbs")/("1 kg") * ("1 m"^(3))/(10^(6)"mL") = 3.00 * 10^(-2)"lbs"/"mL}$

Now all you have to do is use the formula for density to determine volume

V = m/(rho) = ("1.00 lbs")/(3.00 * 10^(-2)"lbs"/"mL") = "33.3 mL"#