# Question 99989

Feb 26, 2015

The specific gravity for your liquid will be $\text{1.33}$.

Specific gravity (SG) is defined as the ratio between the density of a liquid at a certain temperature and the density of water at the same temperature.

Keep in mind that SG must be dimensionless, since it's defined as the ratio of two densities. So, assuming you're at room temperature, the density of water is $\text{1.00 g/mL}$. The density of your liquid is

rho_("liquid") = m/V = "9.30 g"/"7.00 mL" = "1.33 g/mL"#

Therefore, its specific gravity will be

$\text{SG" = rho_("liquid")/rho_("water") = "1.33 g/mL"/"1.00 g/mL" = "1.33}$

If you round this to one sig fig, the number of sig figs $\text{7 mL}$ has, the answer will be

$\text{SG} = 1$

However, I let the answer have three sig figs, you can use whatever suits you best.