What is the molarity if "11 g CaCl"_2" are dissolved in one liter of solution?

Mar 16, 2015

The molarity of CaCl₂ is 0.99 mol/L.

To get the molarity, you divide the moles of solute by the litres of solution.

$\text{Molarity" = "moles of solute"/"litres of solution}$

$\text{Moles of CaCl₂" = 11 cancel("g CaCl₂") ×"1 mol CaCl₂"/(110.98 cancel("g CaCl₂")) = "0.099 mol CaCl₂}$.

$\text{Litres" = "100 mL" = "0.100 L}$

$\text{Molarity" = "moles of solute"/"litres of solution" = "0.099 mol"/"0.100 L" = "0.99 mol/L}$