How many moles of ammonium nitrate are present in "8.047 g" of this substance?

Mar 29, 2015

That much ammonium nitrate contains $\text{0.1005 moles}$.

When you are asked to convert either grams to moles, or moles to grams, always think molar mass.

A compound's molar mass represents the weight of 1 mole of that respective compound. You can either look up the molar mass of ammonium nitrate, $N {H}_{4} N {O}_{3}$, or add the molar masses of the atoms that comprise it.

Since ammonium nitrate's molar mass represents the mass of 1 mole, you can use it to determine how many moles you correspond to that many grams

$\text{molar mass" = "m"/"n" => "n" = "m"/"molar mass}$

In your case, ammonium nitrate's molar mass is 80.052 g/mol, which means that

n = ("8.047"cancel("g"))/("80.052"cancel("g")/"mol") = "0.1005 moles" $N {H}_{4} N {O}_{3}$