Question 9bd40

Apr 13, 2015

The balanced chemical equation for the synthesis reaction of ammonia is

${N}_{2 \left(g\right)} + 3 {H}_{2 \left(g\right)} \to 2 N {H}_{3 \left(g\right)}$

Now, in order to determine the number of liters of ammonia that can be produced, you need the masses of the reactants. The only way to solve for liters produced is to use the number of moles of ammonia produced.

To get the number of moles of ammonia produced, you need the number of moles of nitrogen and the number of moles of hydrogen that react.

If you're able to calculate the number of moles of ammonia produced, you can use the ideal gas law equation to solve for volume

$P V = n R T \implies V = \frac{n R T}{P}$

Here's a sample calculation. Assuming 1 mole of nitrogen and 3 moles of hydrogen react $\to$ according to the $1 : 2$ mole ratio that exists between nitrogen and ammonia, 2 moles of the latter will be produced.

Therefore,

V = (2cancel("moles") * 0.082(cancel("atm") * "L")/(cancel("mol") * cancel("K")) * (273.15 + 27)cancel("K"))/(760/760cancel("atm")) = "49.2 L"#

SIDE NOTE Do not forget to convert the temperature from degrees Celsius to Kelvin and the pressure, which I assume is in mmHg or torr, to atm.